What is the inverse of f(x)=(7+4x)/(19-3x) ?

The inverse of f(x)=(7+4x)/(19-3x) is -(7-19x)/(4+3x)

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inverse of f(x)=(7+4x)/(19-3x)

inverse

f (x) = \frac{7 + 4 x}{19 - 3 x}

- \frac{7 - 19 x}{4 + 3 x}

Solution steps

y = \frac{7 + 4 x}{19 - 3 x}

Replace

x

with

y

x = \frac{7 + 4 y}{19 - 3 y}

Solve for

y, x = \frac{7 + 4 y}{19 - 3 y}

- \frac{7 - 19 x}{4 + 3 x}

f (x) = 7.5 x

f (x) = - 2 \frac{1}{5} x + 1 + 3

\frac{2}{x ^{3}}

\frac{1}{t}

What is the inverse of f(x)=(7+4x)/(19-3x) ?
The inverse of f(x)=(7+4x)/(19-3x) is -(7-19x)/(4+3x)