What is the inverse of g(x)=(-x+9)/(7+4x) ?

The inverse of g(x)=(-x+9)/(7+4x) is (9-7x)/(4x+1)

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inverse of g(x)=(-x+9)/(7+4x)

inverse

g (x) = \frac{- x + 9}{7 + 4 x}

\frac{9 - 7 x}{4 x + 1}

Solution steps

y = \frac{- x + 9}{7 + 4 x}

Replace

x

with

y

x = \frac{- y + 9}{7 + 4 y}

Solve for

y, x = \frac{- y + 9}{7 + 4 y}

\frac{9 - 7 x}{4 x + 1}

f (x) = lo g_{2} (7 x - 10)

y = 41 - 1.25 h

2 x^{2} - 12 x + 5

x + 3 - 9

f (x) = lo g_{2} (a x - 4)

What is the inverse of g(x)=(-x+9)/(7+4x) ?
The inverse of g(x)=(-x+9)/(7+4x) is (9-7x)/(4x+1)