What is the inverse of f(x)=ln(x^2)-7 ?

The inverse of f(x)=ln(x^2)-7 is sqrt(e^{x+7)},-sqrt(e^{x+7)}

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inverse of f(x)=ln(x^2)-7

inverse

f (x) = ln (x^{2}) - 7

e^{x + 7}, - e^{x + 7}

Solution steps

y = ln (x^{2}) - 7

Replace

x

with

y

x = ln (y^{2}) - 7

Solve for

y, x = ln (y^{2}) - 7

e^{x + 7}, - e^{x + 7}

f (x) = \frac{6 x - 9}{20}

f (x) = 7 - x + 2

f (x) = - x - 3 - 2

f (x) = 5 + 1 0^{2 - x}

f (x) = \frac{1}{( x ^{2} - 1 )}

What is the inverse of f(x)=ln(x^2)-7 ?
The inverse of f(x)=ln(x^2)-7 is sqrt(e^{x+7)},-sqrt(e^{x+7)}