What is the inverse of f(x)=5+10^{2-sqrt(x)} ?

The inverse of f(x)=5+10^{2-sqrt(x)} is (ln^2(x-5))/(ln^2(10))-(4ln(x-5))/(ln(10))+4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=5+10^{2-sqrt(x)}

inverse

f (x) = 5 + 1 0^{2 - x}

\frac{ln ^{2} ( x - 5 )}{ln ^{2} ( 10 )} - \frac{4 ln ( x - 5 )}{ln ( 10 )} + 4

Solution steps

y = 5 + 1 0^{2 - x}

Replace

x

with

y

x = 5 + 1 0^{2 - y}

Solve for

y, x = 5 + 1 0^{2 - y}

\frac{ln ^{2} ( x - 5 )}{ln ^{2} ( 10 )} - \frac{4 ln ( x - 5 )}{ln ( 10 )} + 4

f (x) = \frac{1}{( x ^{2} - 1 )}

f (x) = 13 + 3 x

f (x) = x^{2} - 2 x - 1

f (x) = x^{2} - 2 x - 7

3 lo g_{10} (2 x - 2) + 4

What is the inverse of f(x)=5+10^{2-sqrt(x)} ?
The inverse of f(x)=5+10^{2-sqrt(x)} is (ln^2(x-5))/(ln^2(10))-(4ln(x-5))/(ln(10))+4