What is the inverse of 3log_{10}(2x-2)+4 ?

The inverse of 3log_{10}(2x-2)+4 is (10^{(x-4)/3}+2)/(2)

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inverse of 3log_{10}(2x-2)+4

inverse

3 lo g_{10} (2 x - 2) + 4

\frac{1 0 ^{\frac{x - 4}{3}} + 2}{2}

Solution steps

y = 3 lo g_{10} (2 x - 2) + 4

Replace

x

with

y

x = 3 lo g_{10} (2 y - 2) + 4

Solve for

y, x = 3 lo g_{10} (2 y - 2) + 4

\frac{1 0 ^{\frac{x - 4}{3}} + 2}{2}

f (x) = 4 x + 10

f (x) = 4 e^{x}

\frac{8}{3 x + 1}

f (x) = \frac{5}{8 x + 1}

f (x) = \frac{3 x + 1}{2 x - 2}

What is the inverse of 3log_{10}(2x-2)+4 ?
The inverse of 3log_{10}(2x-2)+4 is (10^{(x-4)/3}+2)/(2)