What is the inverse of f(x)=(3x+1)/(2x-2) ?

The inverse of f(x)=(3x+1)/(2x-2) is (1+2x)/(2x-3)

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inverse of f(x)=(3x+1)/(2x-2)

inverse

f (x) = \frac{3 x + 1}{2 x - 2}

\frac{1 + 2 x}{2 x - 3}

Solution steps

y = \frac{3 x + 1}{2 x - 2}

Replace

x

with

y

x = \frac{3 y + 1}{2 y - 2}

Solve for

y, x = \frac{3 y + 1}{2 y - 2}

\frac{1 + 2 x}{2 x - 3}

\frac{s}{s ^{2} + 2 s + 5}

\frac{( 2 x - 5 )}{x - 7}

f (x) = \frac{4}{3 x - 2}

f (x) = \frac{( 3 x - 2 )}{x}

f (x) = \frac{4 - x ^{2}}{3}

What is the inverse of f(x)=(3x+1)/(2x-2) ?
The inverse of f(x)=(3x+1)/(2x-2) is (1+2x)/(2x-3)