What is the inverse of g(x)=2(x+1)^2-10 ?

The inverse of g(x)=2(x+1)^2-10 is sqrt((x+10)/2)-1,-sqrt((x+10)/2)-1

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inverse of g(x)=2(x+1)^2-10

inverse

g (x) = 2 (x + 1)^{2} - 10

\frac{x + 10}{2} - 1, - \frac{x + 10}{2} - 1

Solution steps

y = 2 (x + 1)^{2} - 10

Replace

x

with

y

x = 2 (y + 1)^{2} - 10

Solve for

y, x = 2 (y + 1)^{2} - 10

\frac{x + 10}{2} - 1, - \frac{x + 10}{2} - 1

\frac{2 x - 3}{x}

f (x) = \frac{3 x - 4}{9}

f (x) = (\frac{1}{10 - x}) + 2

f (x) = 5^{3 x}

f (x) = 15 x^{3} - 5

What is the inverse of g(x)=2(x+1)^2-10 ?
The inverse of g(x)=2(x+1)^2-10 is sqrt((x+10)/2)-1,-sqrt((x+10)/2)-1