What is the inverse of f(x)=(x+3)^2-7 ?

The inverse of f(x)=(x+3)^2-7 is sqrt(x+7)-3,-sqrt(x+7)-3

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inverse of f(x)=(x+3)^2-7

inverse

f (x) = (x + 3)^{2} - 7

x + 7 - 3, - x + 7 - 3

Solution steps

y = (x + 3)^{2} - 7

Replace

x

with

y

x = (y + 3)^{2} - 7

Solve for

y, x = (y + 3)^{2} - 7

x + 7 - 3, - x + 7 - 3

f (x) = e^{4 x - 9}

f (x) = \frac{2 x + 3}{x - 3}

f (x) = 2 (x - 6)^{\frac{1}{3}} + 10

f (x) = - 2 + 6

What is the inverse of f(x)=(x+3)^2-7 ?
The inverse of f(x)=(x+3)^2-7 is sqrt(x+7)-3,-sqrt(x+7)-3