What is the inverse of f(x)=240-2x+2x^2+1200 ?

The inverse of f(x)=240-2x+2x^2+1200 is (1+sqrt(2x-2879))/2 ,(1-sqrt(2x-2879))/2

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inverse of f(x)=240-2x+2x^2+1200

inverse

f (x) = 240 - 2 x + 2 x^{2} + 1200

\frac{1 + 2 x - 2879}{2}, \frac{1 - 2 x - 2879}{2}

Solution steps

y = 240 - 2 x + 2 x^{2} + 1200

Replace

x

with

y

x = 240 - 2 y + 2 y^{2} + 1200

Solve for

y, x = 240 - 2 y + 2 y^{2} + 1200

\frac{1 + 2 x - 2879}{2}, \frac{1 - 2 x - 2879}{2}

f (x) = p (t) = 6 t + 8

arcsinh (x)

g (x) = x - 1

What is the inverse of f(x)=240-2x+2x^2+1200 ?
The inverse of f(x)=240-2x+2x^2+1200 is (1+sqrt(2x-2879))/2 ,(1-sqrt(2x-2879))/2