What is the inverse of \sqrt[5]{x}+1 ?

The inverse of \sqrt[5]{x}+1 is x^5-5x^4+10x^3-10x^2+5x-1

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inverse of \sqrt[5]{x}+1

inverse

x^{5} - 5 x^{4} + 10 x^{3} - 10 x^{2} + 5 x - 1

Solution steps

Replace

x

with

y

Solve for

x^{5} - 5 x^{4} + 10 x^{3} - 10 x^{2} + 5 x - 1

f (x) = - 3^{x + 1}

f (x) = (x - 4)^{3} - 7

f (x) = 4 x^{- \frac{3}{5}}

- x - 5 - 2

f (x) = 11 - x^{3}

What is the inverse of \sqrt[5]{x}+1 ?
The inverse of \sqrt[5]{x}+1 is x^5-5x^4+10x^3-10x^2+5x-1