What is the inverse of r/((r-3)^2)*(r^2-9)/(2r) ?

The inverse of r/((r-3)^2)*(r^2-9)/(2r) is (3+6r)/(2r-1)

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inverse of r/((r-3)^2)*(r^2-9)/(2r)

inverse

\frac{r}{( r - 3 ) ^{2}} \cdot \frac{r ^{2} - 9}{2 r}

\frac{3 + 6 r}{2 r - 1}

Solution steps

y = \frac{r}{( r - 3 ) ^{2}} \cdot \frac{r ^{2} - 9}{2 r}

Replace

r

with

y

r = \frac{y}{( y - 3 ) ^{2}} \cdot \frac{y ^{2} - 9}{2 y}

Solve for

y, r = \frac{y}{( y - 3 ) ^{2}} \cdot \frac{y ^{2} - 9}{2 y}

\frac{3 + 6 r}{2 r - 1}

h (x) = 3 x + 8

8^{x - 3}

f (x) = e^{(1 - 4 x^{- 3})}

\frac{7 x}{x + 2}

f (x) = 9 x + 4

What is the inverse of r/((r-3)^2)*(r^2-9)/(2r) ?
The inverse of r/((r-3)^2)*(r^2-9)/(2r) is (3+6r)/(2r-1)