What is the inverse of f(x)=e^{(1-4x^{-3})} ?

The inverse of f(x)=e^{(1-4x^{-3})} is -\sqrt[3]{4/(ln(x)-1)}

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inverse of f(x)=e^{(1-4x^{-3})}

inverse

f (x) = e^{(1 - 4 x^{- 3})}

Solution steps

y = e^{1 - 4 x^{- 3}}

Replace

x

with

y

x = e^{1 - 4 y^{- 3}}

Solve for

y, x = e^{1 - 4 y^{- 3}}

\frac{7 x}{x + 2}

f (x) = 9 x + 4

f (x) = \frac{4 \cdot 3 ^{x}}{6 + 3 ^{x}}

f (x) = 3 x^{\frac{3}{2}}

y = 3 x^{2} + 12 x - 7

What is the inverse of f(x)=e^{(1-4x^{-3})} ?
The inverse of f(x)=e^{(1-4x^{-3})} is -\sqrt[3]{4/(ln(x)-1)}