What is the inverse of y=3x^2+12x-7 ?

The inverse of y=3x^2+12x-7 is (-12+sqrt(12x+228))/6 ,(-12-sqrt(12x+228))/6

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inverse of y=3x^2+12x-7

inverse

y = 3 x^{2} + 12 x - 7

\frac{- 12 + 12 x + 228}{6}, \frac{- 12 - 12 x + 228}{6}

Solution steps

y = 3 x^{2} + 12 x - 7

Replace

x

with

y

x = 3 y^{2} + 12 y - 7

Solve for

y, x = 3 y^{2} + 12 y - 7

\frac{- 12 + 12 x + 228}{6}, \frac{- 12 - 12 x + 228}{6}

f (x) = (x - 7)^{2}, x \geq 7

\frac{1}{5} x - 3

f (x) = \frac{3 x + 1}{2 - x}

f (x) = \frac{3 x + 4}{8}

\frac{x + 3}{5 x - 2}

What is the inverse of y=3x^2+12x-7 ?
The inverse of y=3x^2+12x-7 is (-12+sqrt(12x+228))/6 ,(-12-sqrt(12x+228))/6