What is the inverse of (s-2)/(s^2+1) ?

The inverse of (s-2)/(s^2+1) is (1+sqrt(1-4s(s+2)))/(2s),(1-sqrt(1-4s(s+2)))/(2s)

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inverse of (s-2)/(s^2+1)

inverse

\frac{s - 2}{s ^{2} + 1}

\frac{1 + 1 - 4 s ( s + 2 )}{2 s}, \frac{1 - 1 - 4 s ( s + 2 )}{2 s}

Solution steps

y = \frac{s - 2}{s ^{2} + 1}

Replace

s

with

y

s = \frac{y - 2}{y ^{2} + 1}

Solve for

y, s = \frac{y - 2}{y ^{2} + 1}

\frac{1 + 1 - 4 s ( s + 2 )}{2 s}, \frac{1 - 1 - 4 s ( s + 2 )}{2 s}

f (x) = \frac{x + 1}{x}, x \neq = 0

- \frac{3}{x + 4}

f (x) = \frac{4 x - 2}{x + 3}

f (x) = 3 (x - 5) + 8

What is the inverse of (s-2)/(s^2+1) ?
The inverse of (s-2)/(s^2+1) is (1+sqrt(1-4s(s+2)))/(2s),(1-sqrt(1-4s(s+2)))/(2s)