What is the inverse of f(x)=((x-1))/((1+4x)) ?

The inverse of f(x)=((x-1))/((1+4x)) is (-1-x)/(4x-1)

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inverse of f(x)=((x-1))/((1+4x))

inverse

f (x) = \frac{( x - 1 )}{( 1 + 4 x )}

\frac{- 1 - x}{4 x - 1}

Solution steps

y = \frac{x - 1}{1 + 4 x}

Replace

x

with

y

x = \frac{y - 1}{1 + 4 y}

Solve for

y, x = \frac{y - 1}{1 + 4 y}

\frac{- 1 - x}{4 x - 1}

f (x) = 6 (x + 7)

f (x) = lo g_{10} (x + 7) - 5

f (x) = 6 (x + 3)

f (x) = \frac{( 3 x ^{2} + 4 )}{8}

7 - x

What is the inverse of f(x)=((x-1))/((1+4x)) ?
The inverse of f(x)=((x-1))/((1+4x)) is (-1-x)/(4x-1)