What is the inverse of f(x)=((3x-2))/((x+5)) ?

The inverse of f(x)=((3x-2))/((x+5)) is (-2-5x)/(x-3)

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inverse of f(x)=((3x-2))/((x+5))

inverse

f (x) = \frac{( 3 x - 2 )}{( x + 5 )}

\frac{- 2 - 5 x}{x - 3}

Solution steps

y = \frac{3 x - 2}{x + 5}

Replace

x

with

y

x = \frac{3 y - 2}{y + 5}

Solve for

y, x = \frac{3 y - 2}{y + 5}

\frac{- 2 - 5 x}{x - 3}

f (x) = \frac{( 1 + x )}{( 1 - x )}

f (x) = 1 + 3 x

\frac{6}{x + 1}

f (x) = \frac{x}{4} + 5, - 3 \leq x \leq 4

What is the inverse of f(x)=((3x-2))/((x+5)) ?
The inverse of f(x)=((3x-2))/((x+5)) is (-2-5x)/(x-3)