What is the inverse of f(x)=4x^2+32x+55 ?

The inverse of f(x)=4x^2+32x+55 is (-8+sqrt(x+9))/2 ,-(sqrt(x+9)+8)/2

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inverse of f(x)=4x^2+32x+55

inverse

f (x) = 4 x^{2} + 32 x + 55

\frac{- 8 + x + 9}{2}, - \frac{x + 9 + 8}{2}

Solution steps

y = 4 x^{2} + 32 x + 55

Replace

x

with

y

x = 4 y^{2} + 32 y + 55

Solve for

y, x = 4 y^{2} + 32 y + 55

\frac{- 8 + x + 9}{2}, - \frac{x + 9 + 8}{2}

f (x) = \frac{1 - 3 x}{2 x + 1}

f (x) = x \frac{1}{3} - 9

- \frac{2}{x + 1}

f (x) = \frac{2 x - 9}{3}

k

What is the inverse of f(x)=4x^2+32x+55 ?
The inverse of f(x)=4x^2+32x+55 is (-8+sqrt(x+9))/2 ,-(sqrt(x+9)+8)/2