What is the inverse of f(x)=7(x^{1/5}+7) ?

The inverse of f(x)=7(x^{1/5}+7) is (x^5}{16807}-(5x^4)/(343)+\frac{10x^3)/7-70x^2+1715x-16807

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=7(x^{1/5}+7)

inverse

f (x) = 7 (x^{\frac{1}{5}} + 7)

\frac{x ^{5}}{16807} - \frac{5 x ^{4}}{343} + \frac{10 x ^{3}}{7} - 70 x^{2} + 1715 x - 16807

Solution steps

y = 7 (x^{\frac{1}{5}} + 7)

Replace

x

with

y

x = 7 (y^{\frac{1}{5}} + 7)

Solve for

y, x = 7 (y^{\frac{1}{5}} + 7)

\frac{x ^{5}}{16807} - \frac{5 x ^{4}}{343} + \frac{10 x ^{3}}{7} - 70 x^{2} + 1715 x - 16807

f (s) = \frac{1}{s ^{3} + a ^{3}}

f (x) = 5 x^{2} + 7

f (x) = 5 x^{2} + 4

4 (x - 11)^{2}

f (x) = 5 x - 27

What is the inverse of f(x)=7(x^{1/5}+7) ?
The inverse of f(x)=7(x^{1/5}+7) is (x^5}{16807}-(5x^4)/(343)+\frac{10x^3)/7-70x^2+1715x-16807