What is the inverse of f(x)=\sqrt[5]{x-1}-1 ?

The inverse of f(x)=\sqrt[5]{x-1}-1 is x^5+5x^4+10x^3+10x^2+5x+2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=\sqrt[5]{x-1}-1

inverse

x^{5} + 5 x^{4} + 10 x^{3} + 10 x^{2} + 5 x + 2

Solution steps

Replace

x

with

y

Solve for

x^{5} + 5 x^{4} + 10 x^{3} + 10 x^{2} + 5 x + 2

f (x) = 2 x^{2} - 4 x - 6

5 x^{2} - 2

f (x) = 3 x^{\frac{1}{5}} - 1

f (x) = 4 x - 12

f (x) = (x - 4)^{2}, x \leq 4

What is the inverse of f(x)=\sqrt[5]{x-1}-1 ?
The inverse of f(x)=\sqrt[5]{x-1}-1 is x^5+5x^4+10x^3+10x^2+5x+2