What is the inverse of f(x)=(x-4)^2,x<= 4 ?

The inverse of f(x)=(x-4)^2,x<= 4 is sqrt(x)+4,-sqrt(x)+4

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inverse of f(x)=(x-4)^2,x<= 4

inverse

f (x) = (x - 4)^{2}, x \leq 4

x + 4, - x + 4

Solution steps

y = (x - 4)^{2}

Replace

x

with

y

x = (y - 4)^{2}

Solve for

y, x = (y - 4)^{2}

x + 4, - x + 4

f (x) = 2 x + 7

\frac{d}{d} 7 x + x + 50

f (x) = x + 3 + 1

f (x) = \frac{8 - 5 x}{3}

f (x) = - \frac{7}{( 1 + 4 x )}

What is the inverse of f(x)=(x-4)^2,x<= 4 ?
The inverse of f(x)=(x-4)^2,x<= 4 is sqrt(x)+4,-sqrt(x)+4