What is the inverse of-x+sqrt(16-x) ?

The inverse of-x+sqrt(16-x) is (-2x-1+sqrt(4x+65))/2 ,(-2x-1-sqrt(4x+65))/2

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inverse of-x+sqrt(16-x)

inverse

- x + 16 - x

\frac{- 2 x - 1 + 4 x + 65}{2}, \frac{- 2 x - 1 - 4 x + 65}{2}

Solution steps

y = - x + 16 - x

Replace

x

with

y

x = - y + 16 - y

Solve for

y, x = - y + 16 - y

\frac{- 2 x - 1 + 4 x + 65}{2}, \frac{- 2 x - 1 - 4 x + 65}{2}

\frac{3 x}{7 x - 3}

f (x) = \frac{( - 2 x - 7 )}{( 6 x + 8 )}

f (x) = \frac{x ^{2}}{4} - 1

f (x) = 8 x + 24

f (x) = \frac{( 3 x - 7 )}{( 4 x + 3 )}

What is the inverse of-x+sqrt(16-x) ?
The inverse of-x+sqrt(16-x) is (-2x-1+sqrt(4x+65))/2 ,(-2x-1-sqrt(4x+65))/2