What is the inverse of f(x)=\sqrt[5]{x}+3 ?

The inverse of f(x)=\sqrt[5]{x}+3 is x^5-15x^4+90x^3-270x^2+405x-243

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inverse of f(x)=\sqrt[5]{x}+3

inverse

x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 243

Solution steps

Replace

x

with

y

Solve for

x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 243

f (x) = \frac{5 x - 1}{x + 2}

f (x) = - 2 x - 3

f (x) = 2 x^{2} + 8 x - 42

f (x) = \frac{4 x + 1}{x - 1}

f (x) = \frac{3 x - 1}{4 - 2 x}

What is the inverse of f(x)=\sqrt[5]{x}+3 ?
The inverse of f(x)=\sqrt[5]{x}+3 is x^5-15x^4+90x^3-270x^2+405x-243