What is the inverse of f(x)=(12)/(x^2+1) ?

The inverse of f(x)=(12)/(x^2+1) is sqrt((12-x)/x),-sqrt((12-x)/x)

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inverse of f(x)=(12)/(x^2+1)

inverse

f (x) = \frac{12}{x ^{2} + 1}

\frac{12 - x}{x}, - \frac{12 - x}{x}

Solution steps

y = \frac{12}{x ^{2} + 1}

Replace

x

with

y

x = \frac{12}{y ^{2} + 1}

Solve for

y, x = \frac{12}{y ^{2} + 1}

\frac{12 - x}{x}, - \frac{12 - x}{x}

f (x) = \frac{x + 20}{20 x - 1}

y = - 3 x + 5

(y + 9) = \frac{5}{7} (x - 7)

f (x) = 2 x + 3 - 4

f (x) = \frac{( x ^{2} - 16 )}{x ^{2} - 6 x + 8}

What is the inverse of f(x)=(12)/(x^2+1) ?
The inverse of f(x)=(12)/(x^2+1) is sqrt((12-x)/x),-sqrt((12-x)/x)