What is the domain of f(x)=(2x^2-6x+4)/(-3x-5) ?

The domain of f(x)=(2x^2-6x+4)/(-3x-5) is x -5/3

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domain of f(x)=(2x^2-6x+4)/(-3x-5)

domain

f (x) = \frac{2 x ^{2} - 6 x + 4}{- 3 x - 5}

x < - \frac{5}{3} or x > - \frac{5}{3}

Interval Notation

(- \infty, - \frac{5}{3}) \cup (- \frac{5}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{5}{3}

The function domain

x < - \frac{5}{3} or x > - \frac{5}{3}

\frac{x ^{2} + 1}{x - 3}

\frac{2 x ^{2} - 6 x + 4}{- 3 x - 5}

\frac{2 x ^{2}}{x ^{2} - 1}

\frac{1 - 2 x}{x - 2}

f (x) = \frac{x + 2}{x ^{2} - 121}

What is the domain of f(x)=(2x^2-6x+4)/(-3x-5) ?
The domain of f(x)=(2x^2-6x+4)/(-3x-5) is x<-5/3 \lor x>-5/3