What is the domain of f(x)=(x^2+x+1)/x ?

The domain of f(x)=(x^2+x+1)/x is x 0

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domain of f(x)=(x^2+x+1)/x

domain

f (x) = \frac{x ^{2} + x + 1}{x}

x < 0 or x > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0

The function domain

x < 0 or x > 0

y = \frac{x ^{2} + 1}{x - 3}

f (x) = x (x - 3)^{- \frac{1}{4}}

f (x) = \frac{x - 2 + 2}{x ^{2} - 9}

∣ - 3 x ∣

y = \frac{2 x ^{2} - 6 x + 4}{- 3 x - 5}

What is the domain of f(x)=(x^2+x+1)/x ?
The domain of f(x)=(x^2+x+1)/x is x<0\lor x>0