What is the domain of f(x)=sqrt(2x-2) ?

The domain of f(x)=sqrt(2x-2) is x>= 1

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domain of f(x)=sqrt(2x-2)

domain

f (x) = 2 x - 2

x \geq 1

Interval Notation

[1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 1

The function domain

x \geq 1

f (x) = \frac{2 x + 5}{x ^{2} - 1}

f (x) = (x + 3)^{2}

f (x) = \frac{1}{x ^{2} - 4 x + 3}

f (x) = \frac{2 - x}{3 x ^{3} + 4 x ^{2}}

f (x) = \frac{x ^{5} + 1}{( x ^{2} - 1 ) ^{2}}