What is the domain of f(x)=sqrt(1-4x^2) ?

The domain of f(x)=sqrt(1-4x^2) is -1/2 <= x<= 1/2

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domain of f(x)=sqrt(1-4x^2)

domain

f (x) = 1 - 4 x^{2}

- \frac{1}{2} \leq x \leq \frac{1}{2}

Interval Notation

[- \frac{1}{2}, \frac{1}{2}]

Solution steps

Find non-negative values for radicals:

- \frac{1}{2} \leq x \leq \frac{1}{2}

The function domain

- \frac{1}{2} \leq x \leq \frac{1}{2}

f (x) = 4 + x + 2

y = 5 x + 1

f (x) = lo g_{x - 3} (x^{2} - 4)

f (x) = \frac{( x ^{2} + 1 )}{x - 3}

f (x) = e^{1 - 4 x^{- 3}}

What is the domain of f(x)=sqrt(1-4x^2) ?
The domain of f(x)=sqrt(1-4x^2) is -1/2 <= x<= 1/2