What is the domain of f(x)=((x^2+1))/(x-3) ?

The domain of f(x)=((x^2+1))/(x-3) is x 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=((x^2+1))/(x-3)

domain

f (x) = \frac{( x ^{2} + 1 )}{x - 3}

x < 3 or x > 3

Interval Notation

(- \infty, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3

The function domain

x < 3 or x > 3

f (x) = e^{1 - 4 x^{- 3}}

f (x) = x + 2 + \frac{1}{3 - x}

f (x) = \frac{x ^{2}}{x ^{2} - 1}

f (x) = \frac{x - 1}{x - 2}

f (x) = 3 - x + \frac{1}{x + 2}

What is the domain of f(x)=((x^2+1))/(x-3) ?
The domain of f(x)=((x^2+1))/(x-3) is x<3\lor x>3