What is the domain of f(x)=sqrt(x-2)+sqrt(6-x) ?

The domain of f(x)=sqrt(x-2)+sqrt(6-x) is 2<= x<= 6

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domain of f(x)=sqrt(x-2)+sqrt(6-x)

domain

f (x) = x - 2 + 6 - x

2 \leq x \leq 6

Interval Notation

[2, 6]

Solution steps

Find non-negative values for radicals:

2 \leq x \leq 6

The function domain

2 \leq x \leq 6

2 x - 6

f (x) = 2 - x - x^{2}

y = lo g_{10} (x)

f (x) = ln (ln (x))

f (x) = \frac{1 - x}{x + 2}

What is the domain of f(x)=sqrt(x-2)+sqrt(6-x) ?
The domain of f(x)=sqrt(x-2)+sqrt(6-x) is 2<= x<= 6