What is the domain of f(x)=((x+1))/((x^2-1)) ?

The domain of f(x)=((x+1))/((x^2-1)) is x 1

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domain of f(x)=((x+1))/((x^2-1))

domain

f (x) = \frac{( x + 1 )}{( x ^{2} - 1 )}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

(0, 0), (4, 6)

9

y = - 5 x + 4

2 x - 3 y = 6, (- 2, - 3)

f (x) = \frac{x ^{3} - 3 x ^{2} - 4 x}{x - 4}

What is the domain of f(x)=((x+1))/((x^2-1)) ?
The domain of f(x)=((x+1))/((x^2-1)) is x<-1\lor-1<x<1\lor x>1