What is the domain of f(x)= 1/(2-x^2) ?

The domain of f(x)= 1/(2-x^2) is x sqrt(2)

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domain of f(x)= 1/(2-x^2)

domain

f (x) = \frac{1}{2 - x ^{2}}

x < - 2 or - 2 < x < 2 or x > 2

Interval Notation

(- \infty, - 2) \cup (- 2, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 2

The function domain

x < - 2 or - 2 < x < 2 or x > 2

\frac{x - 3}{x + 4}

f (x) = 2^{x} - 4

f (x) = \frac{x ^{2} + 2 x - 1}{2 x - 1}

f (x) = \frac{2 x - 7}{x ^{2} - 5 x + 4}

f (x) = x^{2} e^{x}

What is the domain of f(x)= 1/(2-x^2) ?
The domain of f(x)= 1/(2-x^2) is x<-sqrt(2)\lor-sqrt(2)<x<sqrt(2)\lor x>sqrt(2)