What is the domain of f(x)=(x^2+2x-1)/(2x-1) ?

The domain of f(x)=(x^2+2x-1)/(2x-1) is x 1/2

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domain of f(x)=(x^2+2x-1)/(2x-1)

domain

f (x) = \frac{x ^{2} + 2 x - 1}{2 x - 1}

x < \frac{1}{2} or x > \frac{1}{2}

Interval Notation

(- \infty, \frac{1}{2}) \cup (\frac{1}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{1}{2}

The function domain

x < \frac{1}{2} or x > \frac{1}{2}

f (x) = \frac{2 x - 7}{x ^{2} - 5 x + 4}

f (x) = x^{2} e^{x}

g (x) = x + 1

\frac{1}{( y ^{2} + 1 ) ^{\frac{1}{2}}} y

4 x + 7

What is the domain of f(x)=(x^2+2x-1)/(2x-1) ?
The domain of f(x)=(x^2+2x-1)/(2x-1) is x< 1/2 \lor x> 1/2