What is the domain of f(x)=4+sqrt(x-2) ?

The domain of f(x)=4+sqrt(x-2) is x>= 2

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domain of f(x)=4+sqrt(x-2)

domain

f (x) = 4 + x - 2

x \geq 2

Interval Notation

[2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

The function domain

x \geq 2

\frac{1}{x - 4}

\frac{3 x}{4 x - 3}

\frac{x ^{2} + 3 x - 10}{( x + 1 ) ( x - 3 ) ( x + 5 )}

- 3 + 2 (x + 1)^{4}

f (x) = - \frac{1}{2} x - 3

What is the domain of f(x)=4+sqrt(x-2) ?
The domain of f(x)=4+sqrt(x-2) is x>= 2