What is the extreme f(x)=-x^3+12x-10 ?

The extreme f(x)=-x^3+12x-10 is Minimum(-2,-26),Maximum(2,6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=-x^3+12x-10

extreme points

f (x) = - x^{3} + 12 x - 10

Minimum (- 2, - 26), Maximum (2, 6)

Solution steps

f^{'} (x) = - 3 x^{2} + 12

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < 2,

Decreasing

: 2 < x < \infty

Plug

x = - 2

into

- x^{3} + 12 x - 10 : - 26

Minimum (- 2, - 26)

Plug

x = 2

into

- x^{3} + 12 x - 10 : 6

Maximum (2, 6)

Minimum (- 2, - 26), Maximum (2, 6)

(1, 2), (5, 5)

f (x) = \frac{x - 2}{x ^{2}}

2^{x} + 3

x^{2} ln (\frac{x}{2})

f (x) = \frac{- 2 x - 9}{- 5 x + 6}

What is the extreme f(x)=-x^3+12x-10 ?
The extreme f(x)=-x^3+12x-10 is Minimum(-2,-26),Maximum(2,6)