What is the domain of f(x)=sqrt(x^2+7x+10) ?

The domain of f(x)=sqrt(x^2+7x+10) is x =-2

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domain of f(x)=sqrt(x^2+7x+10)

domain

f (x) = x^{2} + 7 x + 10

x \leq - 5 or x \geq - 2

Interval Notation

(- \infty, - 5] \cup [- 2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 5 or x \geq - 2

The function domain

x \leq - 5 or x \geq - 2

f (x) = - 2 x + 6

f (x) = \frac{1}{5.7 x - 8.1 x ^{2}}

x^{2} - 4 x + 7

g (x) = \frac{5}{x - 4}

lo g_{2} (x + 2)

What is the domain of f(x)=sqrt(x^2+7x+10) ?
The domain of f(x)=sqrt(x^2+7x+10) is x<=-5\lor x>=-2