What is the domain of g(z)=sqrt(-10z-5) ?

The domain of g(z)=sqrt(-10z-5) is z<=-1/2

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domain of g(z)=sqrt(-10z-5)

domain

g (z) = - 10 z - 5

z \leq - \frac{1}{2}

Interval Notation

(- \infty, - \frac{1}{2}]

Solution steps

Find non-negative values for radicals:

z \leq - \frac{1}{2}

The function domain

z \leq - \frac{1}{2}

f (x) = \frac{- 3}{x - 1}

f (x) = ∣ x ∣ + 3

f (x) = x - 2 + x

f (x) = \frac{( 2 - x )}{( x - 3 )}

f (x) = arctan (\frac{1}{x})

What is the domain of g(z)=sqrt(-10z-5) ?
The domain of g(z)=sqrt(-10z-5) is z<=-1/2