What is the domain of f(x)=sqrt(x-2)+x ?

The domain of f(x)=sqrt(x-2)+x is x>= 2

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domain of f(x)=sqrt(x-2)+x

domain

f (x) = x - 2 + x

x \geq 2

Interval Notation

[2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

The function domain

x \geq 2

f (x) = \frac{( 2 - x )}{( x - 3 )}

f (x) = arctan (\frac{1}{x})

f (x) = \frac{x + 8}{x - 2}

\frac{x + 5}{x ^{2} + x - 6}

h (x) = x - 3

What is the domain of f(x)=sqrt(x-2)+x ?
The domain of f(x)=sqrt(x-2)+x is x>= 2