What is the domain of f(x)=sqrt(x-1)-1 ?

The domain of f(x)=sqrt(x-1)-1 is x>= 1

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domain of f(x)=sqrt(x-1)-1

domain

f (x) = x - 1 - 1

x \geq 1

Interval Notation

[1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 1

The function domain

x \geq 1

f (x) = ln (x^{2} + 2 x - 3)

f (x) = \frac{x}{coth ( x - 1 )}

f (x) = - 7 - x

4 - 2 x

\frac{x ^{2} - 1}{x ^{2} + 1}

What is the domain of f(x)=sqrt(x-1)-1 ?
The domain of f(x)=sqrt(x-1)-1 is x>= 1