What is the domain of f(x)=sqrt((x-1))log_{10}(2-x) ?

The domain of f(x)=sqrt((x-1))log_{10}(2-x) is 1<= x<2

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domain of f(x)=sqrt((x-1))log_{10}(2-x)

domain

f (x) = (x - 1) lo g_{10} (2 - x)

1 \leq x < 2

Interval Notation

[1, 2)

Solution steps

Find non-negative values for radicals:

x \geq 1

Find positive values for logs:

x < 2

Combine real regions and undefined points for final function domain

1 \leq x < 2

y = \frac{1}{4 - x ^{2}}

(x + 4)^{2}

f (x) = (\frac{1}{2}) x^{2}

f (x, y) = 1 + 4 - y^{2}

f (x) = \frac{2 x ^{2}}{x ^{2} + 2 x - 35}

What is the domain of f(x)=sqrt((x-1))log_{10}(2-x) ?
The domain of f(x)=sqrt((x-1))log_{10}(2-x) is 1<= x<2