What is the domain of f(x)= 5/(x^2(x-4)) ?

The domain of f(x)= 5/(x^2(x-4)) is x 4

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domain of f(x)= 5/(x^2(x-4))

domain

f (x) = \frac{5}{x ^{2} ( x - 4 )}

x < 0 or 0 < x < 4 or x > 4

Interval Notation

(- \infty, 0) \cup (0, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = 4

The function domain

x < 0 or 0 < x < 4 or x > 4

f (x) = \frac{1}{( x - 3 ) x + 3}

f (x) = - 2 x - 7

f (x) = (4 x - 7) (1 - 3)

f (x) = lo g_{10} (x^{2} - 7 x + 12)

f (x) = - (x - 2)^{2} + 4

What is the domain of f(x)= 5/(x^2(x-4)) ?
The domain of f(x)= 5/(x^2(x-4)) is x<0\lor 0<x<4\lor x>4