What is the domain of f(x)=sqrt((4x-7)(1-3)) ?

The domain of f(x)=sqrt((4x-7)(1-3)) is x<= 7/4

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domain of f(x)=sqrt((4x-7)(1-3))

domain

f (x) = (4 x - 7) (1 - 3)

x \leq \frac{7}{4}

Interval Notation

(- \infty, \frac{7}{4}]

Solution steps

Find non-negative values for radicals:

x \leq \frac{7}{4}

The function domain

x \leq \frac{7}{4}

f (x) = lo g_{10} (x^{2} - 7 x + 12)

f (x) = - (x - 2)^{2} + 4

f (x) = x 9 - x^{2}

(x - 3)^{2} - 1

f (x) = \frac{2 x - 3}{x ^{2} - 5 x + 4}

What is the domain of f(x)=sqrt((4x-7)(1-3)) ?
The domain of f(x)=sqrt((4x-7)(1-3)) is x<= 7/4