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Popular >

midpoint (12,2),(-5,-7)

Solution

midpoint

(12, 2), (- 5, - 7)

Solution

(\frac{7}{2}, - \frac{5}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (12, 2), (x_{2}, y_{2}) = (- 5, - 7)

= (\frac{- 5 + 12}{2}, \frac{- 7 + 2}{2})

Refine

= (\frac{7}{2}, - \frac{5}{2})

Popular Examples

inflection (18)/(x^2+12)inflection points

\frac{18}{x ^{2} + 12}

extreme f(x)=x^2-3 extreme points

f (x) = x^{2} - 3

range of f(x)=(x+2)^2 range

f (x) = (x + 2)^{2}

inverse of f(x)=(x+3)^2+1 inverse

f (x) = (x + 3)^{2} + 1

domain of f(x)=(7x)/(x^2+x-2)domain

f (x) = \frac{7 x}{x ^{2} + x - 2}

Frequently Asked Questions (FAQ)

What is the midpoint (12,2),(-5,-7) ?
The midpoint (12,2),(-5,-7) is (7/2 ,-5/2)