What is the domain of f(x)=sqrt(x^2+5x+4) ?

The domain of f(x)=sqrt(x^2+5x+4) is x =-1

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domain of f(x)=sqrt(x^2+5x+4)

domain

f (x) = x^{2} + 5 x + 4

x \leq - 4 or x \geq - 1

Interval Notation

(- \infty, - 4] \cup [- 1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 4 or x \geq - 1

The function domain

x \leq - 4 or x \geq - 1

x^{3} - 12 x + 1

y = 7

f (x) = \frac{x + 1}{x - 3}

f (x) = ln (\frac{2 + x}{2 - x})

f (x) = 2 x^{2} - 50

What is the domain of f(x)=sqrt(x^2+5x+4) ?
The domain of f(x)=sqrt(x^2+5x+4) is x<=-4\lor x>=-1