What is the domain of f(x)=sqrt(1-x)ln(x+2) ?

The domain of f(x)=sqrt(1-x)ln(x+2) is -2<x<= 1

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domain of f(x)=sqrt(1-x)ln(x+2)

domain

f (x) = 1 - x ln (x + 2)

- 2 < x \leq 1

Interval Notation

(- 2, 1]

Solution steps

Find non-negative values for radicals:

x \leq 1

Find positive values for logs:

x > - 2

Combine real regions and undefined points for final function domain

- 2 < x \leq 1

f (x, y) = x^{2}

f (x) = \frac{x + 2}{5}

f (x) = \frac{2 x ^{2} - 6 x + 4}{3 x - 5}

f (x) = \frac{4 - 3 x}{x + 5}

f (x) = \frac{x - 4}{x ^{2} + 5 x - 36}

What is the domain of f(x)=sqrt(1-x)ln(x+2) ?
The domain of f(x)=sqrt(1-x)ln(x+2) is -2<x<= 1