What is the domain of f(x)= 1/(sqrt(2x-4)) ?

The domain of f(x)= 1/(sqrt(2x-4)) is x>2

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domain of f(x)= 1/(sqrt(2x-4))

domain

f (x) = \frac{1}{2 x - 4}

x > 2

Interval Notation

(2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

x > 2

\frac{x - 2}{x ^{2} - x}

f (x) = \frac{3 sin ( x )}{sin ( 2 x ) + 1}

\frac{x + 6}{x ^{2} - 9}

f (x) = - x^{2} - 13 x - 40

f (x) = \frac{3 x - 5}{9 x + 27}

What is the domain of f(x)= 1/(sqrt(2x-4)) ?
The domain of f(x)= 1/(sqrt(2x-4)) is x>2