What is the domain of (x+6)/(x^2-9) ?

The domain of (x+6)/(x^2-9) is x 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of (x+6)/(x^2-9)

domain

\frac{x + 6}{x ^{2} - 9}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

f (x) = - x^{2} - 13 x - 40

f (x) = \frac{3 x - 5}{9 x + 27}

f (x) = \frac{4 x}{x ^{2} - 4}

f (x) = \frac{1 - x}{x ^{2} + 2 x - 35}

f (x) = \frac{π}{2} - arccos (1 + x - x^{2})

What is the domain of (x+6)/(x^2-9) ?
The domain of (x+6)/(x^2-9) is x<-3\lor-3<x<3\lor x>3