What is the domain of f(x)= pi/2-arccos(1+x-x^2) ?

The domain of f(x)= pi/2-arccos(1+x-x^2) is -1<= x<= 0\lor 1<= x<= 2

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domain of f(x)= pi/2-arccos(1+x-x^2)

domain

f (x) = \frac{π}{2} - arccos (1 + x - x^{2})

- 1 \leq x \leq 0 or 1 \leq x \leq 2

Interval Notation

[- 1, 0] \cup [1, 2]

Solution steps

Find known functions domain restrictions:

- 1 \leq x \leq 0 or 1 \leq x \leq 2

The function domain

- 1 \leq x \leq 0 or 1 \leq x \leq 2

\frac{2 x - 6}{x + 9}

g (x) = 1 - x^{2}

(x^{3} - 1)^{\frac{2}{3}}

3 x + \frac{6}{5}

- x + 4 - 2

What is the domain of f(x)= pi/2-arccos(1+x-x^2) ?
The domain of f(x)= pi/2-arccos(1+x-x^2) is -1<= x<= 0\lor 1<= x<= 2