What is the range of 4/3 cot(1/2 (x-pi/5)) ?

The range of 4/3 cot(1/2 (x-pi/5)) is -infinity <f(x)<infinity

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range of 4/3 cot(1/2 (x-pi/5))

range

\frac{4}{3} cot (\frac{1}{2} (x - \frac{π}{5}))

- \infty < f (x) < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The range of the basic

cot

function is

- \infty < cot (\frac{1}{2} (x - \frac{π}{5})) < \infty

- \infty < cot (\frac{1}{2} (x - \frac{π}{5})) < \infty

Multiply the edges of the range by:

\frac{4}{3}

- \infty < \frac{4}{3} cot (\frac{1}{2} (x - \frac{π}{5})) < \infty

Therefore the range is

- \infty < f (x) < \infty

tan (2 x - 5)

5 (x + 4)^{2} - 1

f (x) = \frac{x ^{2} - 5 x + 6}{x - 3}

f (x) = 0.5 x^{2} - 4 x + 11

Y (x) = \frac{10}{3} x + 19

What is the range of 4/3 cot(1/2 (x-pi/5)) ?
The range of 4/3 cot(1/2 (x-pi/5)) is -infinity <f(x)<infinity