What is the slope of Y(x)= 10/3 x+19 ?

The slope of Y(x)= 10/3 x+19 is m= 10/3

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slope of Y(x)= 10/3 x+19

slope

Y (x) = \frac{10}{3} x + 19

m = \frac{10}{3}

Solution steps

Convert to standard form:

10 x - 3 Y (x) = - 57

Slope using standard form:

m = \frac{10}{3}

m = \frac{10}{3}

f (x) = \frac{5}{2} x + 15

f (x) = \frac{( x - 3 ) ^{2}}{x ^{2}}

f (x) = 2 x^{2} + 6 x - 3

2 y - 8 = - 3 (5 - x)

y = y (y, x) (x - 4) - 5