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Popular >

range of f(x)=2x^2+6x-3

Solution

range

f (x) = 2 x^{2} + 6 x - 3

Solution

f (x) \geq - \frac{15}{2}

+1

Interval Notation

[- \frac{15}{2}, \infty)

Solution steps

Vertex of

2 x^{2} + 6 x - 3 :

Minimum

(- \frac{3}{2}, - \frac{15}{2})

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 2,

Vertex

(x_{v}, y_{v}) = (- \frac{3}{2}, - \frac{15}{2})

f (x) \geq - \frac{15}{2}

Popular Examples

slope ofintercept 2y-8=-3(5-x)slope intercept

2 y - 8 = - 3 (5 - x)

symmetry y=y(y,x)(x-4)-5 symmetry

y = y (y, x) (x - 4) - 5

inverse of f(x)=-sqrt(1-x^2)inverse

f (x) = - 1 - x^{2}

inverse of f(x)=2(x+3)^3 inverse

f (x) = 2 (x + 3)^{3}

periodicity of y=3sin(pix+2)-3 periodicity

y = 3 sin (π x + 2) - 3

Frequently Asked Questions (FAQ)

What is the range of f(x)=2x^2+6x-3 ?
The range of f(x)=2x^2+6x-3 is f(x)>=-15/2